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1.7x^2-56x-3=60
We move all terms to the left:
1.7x^2-56x-3-(60)=0
We add all the numbers together, and all the variables
1.7x^2-56x-63=0
a = 1.7; b = -56; c = -63;
Δ = b2-4ac
Δ = -562-4·1.7·(-63)
Δ = 3564.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-56)-\sqrt{3564.4}}{2*1.7}=\frac{56-\sqrt{3564.4}}{3.4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-56)+\sqrt{3564.4}}{2*1.7}=\frac{56+\sqrt{3564.4}}{3.4} $
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